Anil Satpute
by Anil7pute
1M ago
NCERT 10th Mathematics Exercise 10.2 Topic: Circle We're here to help! If you're looking for resources to help you learn math, you've come to the right place. We have NCERT textbooks, lessons on Circle, and more. Join our community of students and teachers today! Click here for ⇨ NCERT-10-10-Circle - Ex- 10.1 In Q.1 to 3, choose the correct option and give justification. 1. From a point Q, the length of the tangent to a circle is 24 cm, and the distance of Q from the centre is 25 cm. The radius of the circle is (A) 7 cm (B) 12 cm (C) 15 cm (D) 24.5 cm Solution:&nbs ..read more
Anil Satpute
by Anil7pute
1M ago
NCERT 10th Mathematics Exercise 10.1 Topic: 10 Circle We're here to help! If you're looking for resources to help you learn math, you've come to the right place. We have NCERT textbooks, lessons on Circle, and more. Join our community of students and teachers today! Click here for ⇨ NCERT-10-9-Some Applications of Trigonometry - Ex- 9.1 1. How many tangents can a circle have? Ans:  A circle can have infinite tangents due to its unique properties. 1) From Points Outside the Circle: There are infinitely many pairs of tangents for each point outside the circle, as ..read more
Anil Satpute
by Anil7pute
1M ago
NCERT 10th Mathematics Exercise 9.1 Topic: 9 Some Applications of Trigonometry We're here to help! If you're looking for resources to help you learn math, you've come to the right place. Lessons on Some Applications of Trigonometry from the NCERT textbook are solved systematically. Click here for ⇨ NCERT-10-8-Introduction to Trigonometry - Ex- 8.3 EXERCISE 9.1 1.  A circus artist is climbing a 20 m, long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground  ..read more
Anil Satpute
by Anil7pute
1M ago
Anil Satpute
by Anil7pute
2M ago
NCERT 10th Mathematics Exercise 8.2 Topic: 8 Introduction to Trigonometry Click here for ⇨ NCERT-10-8-Introduction to Trigonometry - Ex- 8.1 EXERCISE 8.2 Q 1. Evaluate the following : (i) sin 60° cos 30° + sin 30° cos 60° (ii) 2 tan2 45° + cos2 30° – sin2 60° (iii) [cos 45°] / [sec 30° + cosec 30°] (iv) [sin 30° + tan 45° – cosec 60°] / [sec 30° + cos 60° + cot 45°] (v)  [5 cos2 60° + 4 sec2 30° – tan2 45°] / [sin2 30° + cos2 30°] Solution: (i) sin 60° cos 30° + sin 30° cos 60° 1) Using the above table, a)&nbs ..read more
Anil Satpute
by Anil7pute
2M ago
Anil Satpute
by Anil7pute
2M ago
Note:  This exercise has been excluded from the syllabus. Here’s a set of additional practice problems specifically tailored to help you comprehend the coordinate geometry concepts outlined in the NCERT 10th-grade syllabus. NCERT 10th Mathematics Exercise 7.4 Topic: 7 Coordinate geometry Click here for ⇨ NCERT-10-7-Coordinate-geometry - Ex- 7.3 EXERCISE 7.4 Q 1. Determine the ratio in which the line 2x + y – 4 = 0 divides the line segment joining the points A(2, – 2) and B(3, 7). Explanation: 1) The point P(x, y) divides the segment joining the points A(x1, y1) and B(x2 ..read more
Anil Satpute
by Anil7pute
2M ago
Note:  Here’s a set of additional practice problems specifically tailored to help you comprehend the coordinate geometry concepts outlined in the NCERT 10th-grade syllabus. NCERT 10th Mathematics Exercise 7.3 Topic: 7 Coordinate geometry Click here for ⇨ NCERT-10-7-Coordinate-geometry - Ex- 7.2 EXERCISE 7.3 1. Find the area of the triangle whose vertices are : (i) (2, 3), (–1, 0), (2, – 4)     (ii) (–5, –1), (3, –5), (5, 2) Explanation: 1) Let ABC be any triangle whose vertices are A(x1, y1), B(x2, y2) and C(x3, y3). Area of a triangle = (1/2)[x ..read more
Anil Satpute
by Anil7pute
5M ago
NCERT 10th Mathematics Exercise 7.2 Topic: 7 Coordinate geometry Click here for ⇨ NCERT-10-7-Coordinate-geometry - Ex- 7.1 EXERCISE 7.2 Q 1. Find the coordinates of the point which divides the join of  (–1, 7) and (4, –3) in the ratio 2 : 3. Explanation: 1) The point P(x, y) divides the segment joining the points A(x1, y1) and B(x2, y2) in the ratio m:n, so we have, x = (mx2 + nx1)/(m + n) y = (my2 + ny1)/(m + n) 2) In general P(x, y) = ((mx2 + nx1)/(m + n), (my2 + ny1)/(m + n))  Solution: 1) The point P(x, y) di ..read more
Anil Satpute
by Anil7pute
5M ago
NCERT 10th Mathematics Exercise 7.1 Topic: 7 Coordinate geometry Click here for ⇨ NCERT-10-6-Triangles - Ex- 6.6 EXERCISE 7.1 Q 1. Find the distance between the following pairs of points : (i) (2, 3), (4, 1) (ii) (– 5, 7), (– 1, 3) (iii) (a, b), (– a, – b) Solution: Q2. Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B discussed in Section 7.2. Solution: Q 3. Determine if the points (1, 5), (2, 3) and (– 2, – 11) are collinear. Solution: Q 4. Check whether (5, – 2), (6, 4 ..read more

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