Thread Starter I'm just wondering if anyone can help with this question Follow 1 hour ago 1 hour ago To find scale factor:you would normally do x^2-4/3(x-2). But if you focus on x^2-4/3(x-2) , x^2 divided by x = x and -4 divided by -2 = POSITIVE 2. So the scale factor would be x 2/3.To find area expression: you would do 9 multiplied x 2/3 (scale factor) SQAURED = 9 X (x 2)^2/9. Then the 9s cancel out as they are common =(x 2)^2. (x 2)^2 is tells us the are but the area wants the expression (x^2 4x 4). So the next step we would do is expand the brackets as (x 2)^2 = (x 2)(x 2). (x 2 ..read more

Thread Starter increasing functions using discriminant of first derivitive. Follow 36 minutes ago 36m ago Quote: Originally Posted by sigmagrindset49 The derivative of the cubic represents its gradient, and the derivative is a quadratic. If I assume the cubic is a positive cubic, then it's derivative is a positive quadratic. So the derivative will be "U" shaped. Therefore the gradient come down from infinity, comes down to a minimum, then goes back up to infinity. The discriminant is used to tell us exactly how far down this positive quadratic goes. A positive discriminant me ..read more

Thread Starter AS Edxcel Maths Practise Paper 2023 Follow 1 hour ago 1 hour ago Hi, A Year 12 maths student here. At GCSE there were many predicted papers and youtube videos,is there anything similar at year 1/AS Maths.I've done the old spec and current Edexcel ,AQA and OCR questions on physics and maths tutor. Is there anything you would recommend ? *Edexcel ..read more

Thread Starter Help - I don't understand significance levels Follow 1 minute ago now Quote: Originally Posted by leoishush Attachment 1071381 is this right then? Yes ..read more

Thread Starter Help mechanics Follow 1 minute ago now going up is positive as hi=eight increases going down is negative as height above ground decreases ..read more

Thread Starter Help mechanics Follow 21 minutes ago 21m ago Help I don’t understand why for part b they did the velocity equal to zero how does that show p changing?? Also the writing on the page is from the ms ..read more

Thread Starter Foundation maths Follow 9 minutes ago 9m ago 2 to 5 GCSE maths foundation tier? Possible ..read more

Thread Starter A-level maths help! Follow 22 minutes ago 22m ago Quote: Originally Posted by skyeforster15 34.4N It's in equilibrium ie no resultant force. On a slope it's really 'the norm' to consider directions perpendicular and parallel to the plane ..read more

Thread Starter Help mechanics Follow 31 minutes ago 31m ago Quote: Originally Posted by Alevelhelp.1 Which equation do I use for this question the correct answer is circled s = 1.85 u = 0 v = unknown a = to be found t = 1.5 So which suvat equation involves s, u, a and t ..read more

Thread Starter Edexcel Mechanics A level question - Mock set 3 Follow 19 minutes ago 19m ago Quote: Originally Posted by tiny hobbit I agree with the mark scheme. a=(6t-2)i + 4j so v = (3t^2-2t + c)i + (4t + d)j and we have the initial velocity for finding c and d. Thank you. I can see where my working was flawed ..read more