Tell us what’s happening: Keys must be unique within a dictionary and they can be only immutable data types. This means you cannot use a list or another dictionary as keys. Add another key age to your dictionary and give it the integer number 2 as value. idk what is the problem Your code so far # User Editable Region copper = {'species': 'guinea pig', 'age': '2'} # User Editable Region Your browser information: User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/121.0.0.0 Safari/537.36 OPR/107.0.0.0 Challenge Information: Learn Algorithm ..read more

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ejemplos=[(‘Alegan’,‘Ángela’), (‘Nepal’,‘Panel’), (‘Nacionalista’,‘Altisonancia’), (‘Valora’,‘Álvaro’), (‘Raza’,‘Zara’), (‘Frase’,‘Fresa’), (‘Colinas’,‘Nicolás’), (‘Pagar’,‘Praga’), (‘Integrarla’,‘Inglaterra’), (‘Quieren’,‘Enrique’), (‘Cornisa’,‘Narciso’), (‘Acuerdo’,‘Ecuador’), (‘fotolitográficamente’,‘litofotográficamente’)] salir =False while salir is False: string_1=“” string_2=“” print(“seleccione:\n\tIngrese dos strings y verifique si son anagramas\n\tS) salir”) string_1=input(“Ingrese la primer palabra:”).upper() string_2=input(“Ingrese la segunda palabra:”).upper() if string_1==“S” or ..read more

I am new to the site. I 've been working on Password Gererator and found myself stopped at step 35. Is there a way to review the instructional content with out starting from the begining of the lesson? Or maybe the wording could change, because as it reads, I have no idea., 3 posts - 2 participants Read full topic ..read more

Tell us what’s happening: text = ‘Hello World’ shift = 3 alphabet = ‘abcdefghijklmnopqrstuvwxyz’ index = alphabet.find(text[0]) print(index) print(text.lower) I cannot see what I am doing wrong can anyone help please? It just keeps saying place function call at the beginning of the line but I have? Your code so far # User Editable Region text = 'Hello World' shift = 3 alphabet = 'abcdefghijklmnopqrstuvwxyz' index = alphabet.find(text[0]) print(index) print(text.lower) # User Editable Region Your browser information: User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537 ..read more

Tell us what’s happening: Hi can someone give me this solutions i am trying this for 2 days but I am not able to do this Your code so far # User Editable Region solve_sudoku, puzzle = [ [0, 0, 2, 0, 0, 8, 0, 0, 0], [0, 0, 0, 0, 0, 3, 7, 6, 2], [4, 3, 0, 0, 0, 0, 8, 0, 0], [0, 5, 0, 0, 3, 0, 0, 9, 0], [0, 4, 0, 0, 0, 0, 0, 2, 6], [0, 0, 0, 4, 6, 7, 0, 0, 0], [0, 8, 6, 7, 0, 4, 0, 0, 0], [0, 0, 0, 5, 1, 9, 0, 0, 8], [1, 7, 0, 0, 0, 6, 0, 0, 5] ] # User Editable Region Your browser information: User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHT ..read more

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Tell us what’s happening: i can not understand and go from this step can u help me? Your code so far # User Editable Region text = 'Hello World' shift = 3 alphabet = 'abcdefghijklmnopqrstuvwxyz' for char in text.lower(): index = alphabet.find(char) print(char, index) new_index = index + shift new_char = alphabet[new_index] # User Editable Region Your browser information: User Agent is: Mozilla/5.0 (Windows NT 6.1; rv:107.0) Gecko/20100101 Firefox/107.0 Challenge Information: Learn String Manipulation by Building a Cipher - Step 35 freecodecamp.org freeCodeCamp.org Learn ..read more

Tell us what’s happening: can anyone help me it is showing me some indent error and not able to get it Your code so far User Editable Region Your browser information: User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/124.0.0.0 Safari/537.36 text = 'Hello Zaira' shift = 3 def caesar (): alphabet = 'abcdefghijklmnopqrstuvwxyz' encrypted_text = '' for char in text.lower(): if char == ' ': encrypted_text += char else: index = alphabet.find(char) new_ ..read more

Tell us what’s happening: if all is not performing good why ? I followed the instructions of this step Your code so far import re import secrets import string def generate_password(length, nums, special_chars, uppercase, lowercase): # Define the possible characters for the password letters = string.ascii_letters digits = string.digits symbols = string.punctuation # Combine all characters all_characters = letters + digits + symbols while True: password = '' # Generate password for _ in range(length): password += secrets.choice ..read more