I know it's a guideline to show my work, but I don't even know how to start this problem, so please make an exception. I do know how to do the questions before but I have no clue how to start the last question. How would you solve without knowing the ratios? A guide to the right path will be highly appreciated ..read more

Онлайн Газета 24News працює 24 години на добу для того, щоб виставити Вам самі свіжі новини. Наші журналісти працюють у різних куточках країн щоб швидко добути свіжі події України та Світу. Ми є повністю приватною Сайтом, не заангажованою політиками, Центральною владою або ставлениками олігархів. Ось кілька яскравих тем на сьогодні: • Мессінг про третю світову війну 2024 • Новий закон... Read more ..read more

Сайт 24News працює 24 години цілодобово для того, щоб представити Вам самі топові новини. Наші журналісти перебувають у різних куточках Землі щоб блискавично дістати останні події України та Світу. Ми є повністю приватною Сайтом, не заангажованою політиками, Центральною владою або олігархами. Ось кілька топових тем на сьогодні: • Мессінг про третю світову війну 2024 • Новий закон про... Read more ..read more

I am trying to find the Galois Group G([imath]\mathbb{Q(\sqrt{2}, \sqrt3)}/\mathbb{Q})[/imath]. That means, I have to find the automorphisms [imath]\phi: \mathbb{Q(\sqrt{2}, \sqrt3)} \rightarrow \mathbb{Q(\sqrt{2}, \sqrt3)}[/imath], for which [imath]\phi(x)=x, \forall x \in \mathbb{Q}[/imath]. Let's say K=[imath]\mathbb{Q(\sqrt{2}, \sqrt3)}[/imath]. I am fairly certain that all elements of K can be written as [imath]a + b\sqrt2 +c\sqrt3 + d\sqrt 6[/imath], [imath]a, b, c, d \in \mathbb{Q}[/imath]. I know that if... Read more ..read more

Could you please review the attached image for the question and my answer? I've marked the boundary conditions according to the provided instructions, but there are four additional positions where I'm unsure about setting the boundary conditions. Can you advise on how to set the boundary conditions for these remaining locations? Additionally, could you please confirm whether the marked boundary conditions are correct or incorrect ..read more

How do I solve this ..read more

This glass has vertical sides. The diameter of its base is 68 mm. How many of these glasses will fit of this rectangular tray (28 cm × 42 cm)? Thank you in advance for your help. The correct answer is 24 glasses. Why can't we do the following? Area of the tray = 28 × 42 =1176 cm2. Area of the base= pi x r x r = 36.29 cm2 1176/36.29= 32.40. I saw in my son's year 6 practice book. I know the correct answer is 24 but I still don't know why not 32.40 ..read more

Θ"-Θ=tsint For polynomials it is fairly straight forward what we set equal too. And for just sin and cos we match them just as easily as we do when we have a polynomial But why do we combine them when we have both a polynomial and sin or cos? why not all cosines and sines together or all powers together. Why do we need to do each combination ..read more

Can anyone solve dy/dx= 6e^y sin3x when y=0 and x=0. I cannot get the answer which is y=-ln|-2cosx+3 ..read more

In combinatorics, the twentyfold way (and better known predecessor the twelvefold way) classifies counting problems via a single mathematical framework, functions with certain properties mapping domains with certain properties to codomains with certain properties. While not exhaustive of all combinatorics problems, this gives some structure to the space instead of treating one problem as fundamentally about ice cream, another about table arrangement, another about circular table... Read more ..read more